(05/23/2011, 09:01 PM)sheldonison Wrote: Where \( \theta(z) \) is a 1-cyclic function, which quickly decays to zero as imag(z) increases. Then, the constant "k" is 5.0552093131039000 + 1.0471975511965977*I.
Without looking at numerical values I at least want to mention, if theta is 1-cyclic and bounded (which would follow from decay towards ioo) then theta would be constant, because every bounded entire function must be constant.
PS: you have some typos in the thread title.
