[2015] 4th Zeration from base change pentation

[tommy1729]

In case it was not clear , I think the zeration will be the one that satisfies 2[0]2[0] ... = x + 2 or this one a[0]b = ln(exp(a)+exp(b) ).

The ackermann recursion makes no sense in this context for pentation.

Numerical experiments seem hard at first because of the speed of pentation.

And I have 0 theory.

But maybe others have ideas.

regards

tommy1729