Zeration = inconsistant ?

[GFR]

Hi.
Thanks for your swift reply.
.......
... I tried to reverse everything : define zeration in terms of higher operators , instead of lower , and define distributivity in the REVERSE way.

It was therefore done intentionally !
NOT to try to ridicule or dismiss zeration but rather as an attempt to " fix it ".
I understand it looks like a silly mistake but it was not.
Have a bit more confidence in me
......
regards
tommy1729

No problem. I trust you, Tommy!
As a matter of fact, I think that the higher rank operation should always distribute over the lower rank, if distributivity holds. I mean:
a + (b o c) = (a + b) o (a + c), like: a * (b + c) = ab + ac.

You tried the reverse way and you didn't succeed. I think that it was normal!
Keep it going!

Best regards.

GFR