10/03/2014, 09:41 PM
As for the exp^[a]( ln^[a](x) + ln^[a](y) ) case , I think I have something intresting ; numerical methods independant of a.
Need more research.
Looks promising.
Ok ok , I say a bit more :
solving for x when given a and b :
exp^[a]( 2 ln^[a] (x) ) = b
seems to have a method.
regards
tommy1729
Need more research.
Looks promising.
Ok ok , I say a bit more :
solving for x when given a and b :
exp^[a]( 2 ln^[a] (x) ) = b
seems to have a method.
regards
tommy1729

