(06/09/2014, 10:44 AM)tommy1729 Wrote: I assume mike3 meant :
\( \Gamma(\theta(x)) \)
As for the numerical testing , did mike test for x > 0 or x >-2 or a Taylor series at some x ? Or x > some C ?
If his conjecture means for x > -2 then it is quite a strong idea ,
but Im not sure about existance since going from 0 to 1 is not convex.
SO I assume for x > 0.
Right ?
regards
tommy1729
Um, it should be \( \Gamma(x) \theta(x) \). \( \Gamma(\theta(x)) \) is a 1-periodic function itself and not at all a solution of the Gamma function equations!
Convexity is over odd derivatives (for tetration), and even derivatives (for gamma function).

