06/25/2013, 01:37 PM
(This post was last modified: 06/25/2013, 01:50 PM by sheldonison.)
(06/25/2013, 10:45 AM)Gottfried Wrote:The Kneser complex conjugate solution is only defined for bases>e^(1/e), not for base=sqrt(2), where we normally use regular iteration instead. The Kneser solution is built on a modification of the complex Schroder function solution, but for the Kneser solution, S(0) is always singularity, so there would be no definition for a dual of 0.(06/24/2013, 04:09 PM)sheldonison Wrote: What is the definition/equation for a Kneser solution dual? The Kneser solution is not periodic. Would the dual of -infinity, which is sexp(-2) be sexp(2)?.... if \( K(h,x) \) would denote the Kneser-method iteration from x using height h, then in our case with base = sqrt(2)...
- Sheldon
Gottfried
For the tangent angle sum equation, the Schröder function of the limit as z approaches real infinity is defined and the dual is \( S^{-1} (-S (z - t_0)) + t_0 = 0 \) which is exactly halfway between the two fixed points of -1 and 1. Hope you enjoy working with the alternating sum of the htan function, which is both 2-periodic, and Pi*I periodic, with singularities at Pi*I/2 and 1+Pi*I/2.
- Sheldon

