11/10/2011, 01:20 AM
Okay, alright, that seems reasonable. I just found it misleading that they would write that formula and state that zeration satisfies this property.
I guess it should just be acknowledged that if we want to analytically continue the Ackermann function, zeration doesn't come into play.
I guess it should just be acknowledged that if we want to analytically continue the Ackermann function, zeration doesn't come into play.

