04/29/2009, 06:59 PM
Ansus Wrote:I've verified both and both indeed correct solutions. Mathematica finds \( F(x)=C^{b^x} \) for the general case of \( f(x)=x^b \).
What Maple gives for \( f(x)=\frac{x+a}{x-a} \)?
Nothing
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elementary superfunctions
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