(06/13/2022, 10:48 PM)JmsNxn Wrote: Hey, Catullus. Those are one and the same on the extended real number system.Is not e^-∞ is an infinitesimal? Ln(e^a) does not equal a for all a. For instance, ln(e^iτ)=ln(1)=0. Not iτ.
\[
\log(e^a + e^{-\infty}) = \log(e^a + 0) = \log(e^a) = a\\
\]
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\

