Some "Theorem" on the generalized superfunction
#8
Very damn impressive, Leo.

I'll need sometime to think about this more. I like your examples, though; you're explaining yourself very well. And, again, what I mean is; you as a human are choosing how to perform the black box. Which is to say,

\(
\zeta\{f|h\}
\)

Doesn't have one, single clean formula. I was wondering how you were classifying the choices for \( \zeta\{f|h\} \); and yes, we can perform abel iterations; it's making it reductive to a single algorithm that's the real trouble.

For example, on the real-line. Let's assume we have an analytic super function \( F(z) \) for \( z \) in a neighborhood of the real-line; where here \( f(F(x)) = F(x+1) \). There always exists a perturbation; which is a 1-periodic function \( \theta(z+1) = \theta(z) \) and \( \theta(x) \in \mathbb{R}^+ \) ; where \( F_\theta(x) = F(x + \theta(x)) \). Where now \( F_\theta \) is also a real valued super-function. Furthermore, it's pretty much indistinguishable from any other iteration.

So, as you've introduced it, is a set of functions. The really hard part, is distinguishing between each member of the set.

But again, I'll read over more carefully what you've written tomorrow.
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Messages In This Thread
RE: Some "Theorem" on the generalized superfunction - by JmsNxn - 05/06/2021, 06:23 AM

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