Some "Theorem" on the generalized superfunction
#6
Hey, Leo, very interesting stuff. Don't worry about your English, you speak very well; it's alright.

To add in Latex on this forum just write


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math goes here
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As to what you do with \( \zeta(\tan(z)|\exp(\exp(z))) \); that's very clever. That's particular to what MphLee and I were talking about. I guess my question was more so, how do you plan to choose which superfunction we produce? That was more what I was asking. 

I get that,

\(
\tan(F(z)) = F(z+1)\\
\exp(\exp(G(z))) = G(z+1)\\
\zeta(\tan(z)|\exp(\exp(z))) = F(G^{-1}(z))\\

\)

I was wondering if you had any method where it chooses a particular super function \( F \) and \( G \).

Regards, James
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Messages In This Thread
RE: Some "Theorem" on the generalized superfunction - by JmsNxn - 05/05/2021, 07:53 PM

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