Regular slog for base sqrt(2) - Using z=2
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It's not 18*I, it's \( \frac{2\pi i}{\ln\left(\sqrt{2}\right)} \), which is the periodicity of the logarithm base sqrt(2). The value works out to 18.13*I or so.
~ Jay Daniel Fox
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RE: Regular slog for base sqrt(2) - Using z=2 - by jaydfox - 11/25/2007, 03:18 AM

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