01/13/2016, 09:21 PM
(01/13/2016, 05:36 PM)sheldonison Wrote: Lets say we have the Schroeder function, and its inverse \( S(z)\;\;S^{-1}(z) \) which have corresponding Abel and super functions, \( \alpha(z)=\log_L(S(z))\;\;\alpha^{-1}(z)=S^{-1}(L_0+L^z)\;\; \) Notice that for b=e, \( \exp(z)\; L_0=L\;\; \) but this is not the case for other bases.
So
\( \alpha^{-1}(z)=S^{-1}(L_0+L^z) \)
\( S(\alpha^{-1}(z))=L_0+L^z \)
\( S(z)=L_0+L^{\alpha(z)} \)
\( S(z)=L_0+S(z) \)
\( S(z) - S(z) = L_0 = 0 \)
which means \( L_0 = L = 0 \)?
I don't understand.

