08/25/2015, 08:13 AM
The solution seems to be constructible by using again a superfunction.
Example
F(-x) = e F(x)
Ln(-x) = ln(x) + pi i
Exp(x+1) = e exp(x)
So
F = exp(ln(x)/(pi i)) = x^(- 1/pi i)
Regards
Tommy1729
Example
F(-x) = e F(x)
Ln(-x) = ln(x) + pi i
Exp(x+1) = e exp(x)
So
F = exp(ln(x)/(pi i)) = x^(- 1/pi i)
Regards
Tommy1729

