11/15/2007, 09:44 AM
hej jaydfox,
Thanks. I know how annoying such elementary things can be.
But I would end up with ln(sqrt(2)) +- pi I +- 2pi I k?
Ivars
Thanks. I know how annoying such elementary things can be.
jaydfox Wrote:\( \ln\left(\sqrt{2}\right) \pm (2k+1)\pi i \) or ln(sqrt(2)) +- (2k+1)pi I, or if you really need to factor out k and put it at the end of the expression, then ln(sqrt(2)) + pi I +- 2 pi I k
But I would end up with ln(sqrt(2)) +- pi I +- 2pi I k?
Ivars

