Imaginary zeros of f(z)= z^(1/z) (real valued solutions f(z)>e^(1/e))
#53
Hej Gottfried,

Gottfried Wrote:Ivars -


[attachment=126]


Gottfried


Could there be another symmetrical curve for b=imag(t) ? So that at point 0;0 You will have 2 curves crossing each other?

Then You could take away the left 2 quadrants of the graph totally- I can not understand why they are needed as it seems to me - maybe wrongly- that there beta=-pi/2 also belongs to h(e^pi/2) which can not be true?

Ivars
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Messages In This Thread
RE: Imaginary zeros of f(z)= z^(1/z) (real valued solutions f(z)>e^(1/e)) - by Ivars - 11/14/2007, 04:52 PM
RE: Tetration below 1 - by Gottfried - 09/09/2007, 07:04 AM
RE: The Complex Lambert-W - by Gottfried - 09/09/2007, 04:54 PM
RE: The Complex Lambert-W - by andydude - 09/10/2007, 06:58 AM

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