11/14/2007, 05:38 AM
bo198214 Wrote:So how do you finally compute the \( k \)th branch of \( h \) or \( W \) with this formula?
I think the following two methods are possibly the standard branches of h:
\( h_k(x) = e^{-W_k(-\log(x))} = \frac{W_k(-\log(x))}{-\log(x)} \)
and much easier to compute in my opinion.
Andrew Robbins

