03/17/2015, 11:45 PM
The problem might be
p( f(x) ) = f(ax) + b f(cx)
is nice but does it mean
p^[z] ( f(x) ) = f(a^z x) + b^z f(c^z x)
or does
p^[z] ( f(x) ) = f(a^z x) + b f(c^z x)
or something else ?
I noted that since p(0) = 0 :
Let f(A) = 0
p(f(A)) = f(aA) + b f(cA) = 0
Not sure what to make of that ...
regards
tommy1729
p( f(x) ) = f(ax) + b f(cx)
is nice but does it mean
p^[z] ( f(x) ) = f(a^z x) + b^z f(c^z x)
or does
p^[z] ( f(x) ) = f(a^z x) + b f(c^z x)
or something else ?
I noted that since p(0) = 0 :
Let f(A) = 0
p(f(A)) = f(aA) + b f(cA) = 0
Not sure what to make of that ...
regards
tommy1729

