07/28/2014, 05:06 PM
Remind me why the functional equation for superexponentiation (or the superlogarithm) isn't adequate? I seem to recall that there was an issue with apparent inconsistencies?
sexp(x+1) = exp(sexp(x))
slog(exp(x)) = slog(x)+1
Was it just an issue with branches? If so, is that really a problem?
sexp(x+1) = exp(sexp(x))
slog(exp(x)) = slog(x)+1
Was it just an issue with branches? If so, is that really a problem?
~ Jay Daniel Fox

