05/03/2014, 03:39 AM
(This post was last modified: 05/03/2014, 11:16 PM by sheldonison.)
(05/02/2014, 10:42 PM)tommy1729 Wrote: This is still unresolved.
Despite my increasing understanding of sexp and slog, I do not know how to work with this.
Im confident others here could solve the problem.
regards
tommy1729
Traveling -- little time right now. This is problem is closely related to my mathstack thread; ln-n-of-tetrationx-n-is-nowhere-analytic.
My relevant function is the following equation.
\( f(x) = \lim_{n\to \infty} \ln^{[n]} x \uparrow\uparrow n \)
One of Tommy's original question was
"is there a known series expansion for y^^(n-1) = x^^n ??"
For the limiting answer, as n goes to infinity, given base base x, we use my function above. We desire \( f(y)=e^{f(x)} \), so we calculate \( y=f^{-1}(e^{f(x)}) \). Of course, there is the small issue that f(x) is conjectured coo and nowhere analytic .... I plan to eventually post a proof.
Using the above equation, if b~=7.28550781987618684208203148323, from this mathstack thread
then f(b)=e, and as n goes to infinity, \( b\uparrow\uparrow n = e \uparrow \uparrow (n+1) \)
- Sheldon

