11/17/2011, 07:52 PM
(11/16/2011, 10:57 PM)JmsNxn Wrote: I just got the feeling that you were implying \( f^{\diamond n}(x) \) is inconsistent seperate from the diamond operator; which is not true. It's very simple and nothing about it implies inconsistency, unless you think an infinite sequence of superfunctions is inconsistent.
hmm ...
how does a converging infinite sequence of uniquely defined superfunctions look like any way ?
fractal ??
another question or remark ..
if a superfunction look like ( carleman f(z) ) ^ x , does that imply that fractional superfunction operators look like ( carleman f(z) ) ^ ^ x ?
if so , we need to extend the bases E [1,eta]U[sqrt(e),oo[ to matrix bases ?
does this imply that the (carleman) matrices require |det| = E[1,eta]U[sqrt(e),oo[ ??
again - as usual - many questions , more questions than answers.
regards
tommy1729

