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What am I doing wrong here?

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What am I doing wrong here?
bo198214 Offline
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05/21/2011, 08:04 PM (This post was last modified: 05/21/2011, 08:04 PM by bo198214.)
(05/12/2011, 07:53 PM)JmsNxn Wrote: \( x \bigtriangledown y = \ln(e^x - e^y) \)

One problem could be that if you let x=l then \( x \bigtriangledown l = -\infty \). And calculating with infinities is always somewhat risky.
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Messages In This Thread
What am I doing wrong here? - by JmsNxn - 05/12/2011, 07:53 PM
RE: What am I doing wrong here? - by bo198214 - 05/21/2011, 08:04 PM
RE: What am I doing wrong here? - by JmsNxn - 05/26/2011, 02:21 AM

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