(04/14/2011, 10:57 PM)tommy1729 Wrote: When there is a (local) unique inverse , you might use the so-called " series reversion " for its taylor series at a fixpoint.
Or you might try to express ackermann in terms of sexp slog etc but im not sure its possible.
maybe this has occured in older threads.
you can express the domain [0, 2] using sexp slog algos, it's piece wise though.
but I'll show you what happens; 0 <= q <= 1
\( x\, \{q\}\, y\, =\, -q:ln(q:ln(x)\, +\, q:ln(y))\, = sexp(slog(sexp(slog(x)-q)+sexp(slog(y)-q))+q) \)
solve for q, it's practically impossible; same deal for [1, 2]