since sexp(0) = 0 in the OP ,
we can extend : no bending points on sexp follows from no bending points on its half-iterates.*
( * but not necc in reverse ! possibly invalidating this post )
we can find the half-iterate of sexp by using the fixpoint 0.
f^[2](x)= sexp(x).
generalising this , we end up with no bending points at pent(x).
hence the no bending points condition extends to the whole hierarchy :
tetration , pentation , sextation , ...
tommy1729
we can extend : no bending points on sexp follows from no bending points on its half-iterates.*
( * but not necc in reverse ! possibly invalidating this post )
we can find the half-iterate of sexp by using the fixpoint 0.
f^[2](x)= sexp(x).
generalising this , we end up with no bending points at pent(x).
hence the no bending points condition extends to the whole hierarchy :
tetration , pentation , sextation , ...
tommy1729