10/25/2009, 07:43 AM
(10/25/2009, 02:14 AM)mike3 Wrote: But it's a constant function, so it cannot be interpreted as analytic continuation of the specific function \( \mathrm{tet}_b(z) \) to another branch
Yes you are right, its no more the regular tetration.
Can you say which branch sequence you used to produce the constant function?
Quote:As you can see above, though, if we interpret it in a multivalued sense, that values on some branches of \( \mathrm{tet}_b(z+1) \) equal \( b^{\mathrm{tet}_b(z)} \) for values on some branches of \( \mathrm{tet}_b(z) \), then it is true, ... "Multivalued functions" are funny things, you know?
Indeed I noticed that interpretation already in other contexts. If you have a multivalued function satisfying a certain functional equation it satisfies this equation only if you choose the suitable branches.
Easiest example is log with the functional equation log(ab)=log(a)+log(b).
I remember also this kind of description in [Kuzma: iterative functional equations] for regular holomorphic Abel functions. Particularly I noticed this behaviour with Dmitrii's superlog, and now you add regular tetration.
