Solving tetration for base 0 < b < e^-e
#12
Why do you need to use a complex fixed point for \( b = e^{-e} \)? It converges to a real fixed point as the tower approaches infinity (namely, \( \frac{1}{e} \)).
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RE: Solving tetration for base 0 < b < e^-e - by mike3 - 09/13/2009, 07:24 AM

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