08/11/2009, 01:45 PM
(This post was last modified: 08/11/2009, 01:48 PM by Base-Acid Tetration.)
I think I had something like that before...
see my "hyper-iteration" post.
see my "hyper-iteration" post.
Tetratophile Wrote:Along the same lines as "functional root" \( \sqrt[n]{f}(x), \) (a function which, iterated n times, gives f(x)), the "functional logarithm" can be defined so that \( \operatorname{flog}_f (f^n(x)) = n \) for all n.any differences betweeen bo's terminology and mine? It FEELS different...

