11/19/2008, 03:14 AM
bo198214 Wrote:Proof. Let \( g,h \) be two function that satisfy the above conditions. Then the function \( \delta(z)=g^{-1}(h(z)) \) is holomorphic on \( S \) (because \( h(S)\subseteq G \) and (3)) and satisfies \( h(z)=g(\delta(z)) \)...Why \( h \)? There was no \( h \) above. Should not be \( f \)?

