06/03/2008, 01:13 PM
Ivars Wrote:At least, as a first step
As a first step to what? The proof shows that there is no such function, not even a discontinuous one.
Quote:\( \lim_{x\to\\{-x_o}} f(x_o)= 0, \)
\( \lim_{x\to\\{+x_o}} f(x_o)= 1, \)
Thats not difficult if it is only for one point \( x_0 \). Just define \( f(x)=0 \) for \( x<x_0 \) and \( f(x)=1 \) for \( x>x_0 \) and \( f(x_0) \) as you like.
