08/21/2007, 02:39 AM
Oh, and the combinatorial equation is off by some factorials,
sorry I forgot to include them when substituting \( A_k = A^{(k)}(1)/k! \):
Andrew Robbins
sorry I forgot to include them when substituting \( A_k = A^{(k)}(1)/k! \):
\(
A_n = \sum_{k=n}^{\infty} \left({k \atop n}\right) \sum_{j=0}^k \left{{k \atop j}\right} \frac{j!}{k!} A_j
\)
A_n = \sum_{k=n}^{\infty} \left({k \atop n}\right) \sum_{j=0}^k \left{{k \atop j}\right} \frac{j!}{k!} A_j
\)
Andrew Robbins
