Generalized recursive operators
#32
Ivars Wrote:So what are the exact values for :

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 7 \\\hline\end{tabular} b) = ? \)

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 9\\\hline\end{tabular} b) = ? \)

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 11\\\hline\end{tabular} b) = ? \)

etc?
Well, always for \( b < 0 \) let us start from (Hey, boys, I am starting using TeX ... Waaaoow!):

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 7 \\\hline\end{tabular} b) = c \)

For an estimation of \( c \), I think we may proceed like this, assuming the new more precise asymptotic value obtained by Andydude (step 0):

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 5 \\\hline\end{tabular} b) = -1.85.. \), and:

\( \lim_{b\rightarrow-1.85..}(e \begin{tabular}{|c|}\hline 5 \\\hline\end{tabular} b) = -\infty \)

Then:

step 1 - Calculate \( y = e \begin{tabular}{|c|}\hline 5 \\\hline\end{tabular} b \) vor various values of \( b < 0 \) and produce a graphical continuous and smooth plot, if possible;

step 2 - Produce the graphical inversion of the previous plot, always in the \( b < 0 \) domain, so obtaining the pentalog of \( b < 0 \) ;

step 3 - Estimate the intersection between the two pentation/pentalog diagrams (always in \( b < 0 \)), which should coincide with one the pentation fixpoints for \( y = b \). The coordinate of this point should be what we may call \( h \). This \( h \) is the coordinate of the penta-fixpoint and, therefore of the hexation asymptote. We can see thay it must be \( h < -1.85.. \).

step - Proceed again as in step 3 with the hexation/hexalog plots and the result will be \( c < h \), such that:

\( \lim_{b\rightarrow-\infty}(e \begin{tabular}{|c|}\hline 7 \\\hline\end{tabular} b) = c \), and:

\( \lim_{b\rightarrow c}(e \begin{tabular}{|c|}\hline 7 \\\hline\end{tabular} b) = -\infty \)

And ... so on !!!! Sad
However, ... it is a very long way ... Perghaps there are shortcuts.

GFR
[Sorry, Administrator, these comments of mine, apart the first 5 lines are completely wrong. I shall correct them asap. Perhaps, I was tired! - GFR]
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Messages In This Thread
Generalized recursive operators - by Whiteknox - 11/23/2007, 06:42 AM
RE: Generalized recursive operators - by bo198214 - 11/23/2007, 08:41 AM
RE: Generalized recursive operators - by andydude - 11/25/2007, 01:02 AM
RE: Generalized recursive operators - by andydude - 11/29/2007, 04:45 AM
RE: Generalized recursive operators - by andydude - 11/29/2007, 05:55 AM
RE: Generalized recursive operators - by andydude - 11/29/2007, 06:20 AM
RE: Generalized recursive operators - by andydude - 11/30/2007, 06:12 PM
RE: Generalized recursive operators - by andydude - 11/30/2007, 09:18 PM
RE: Generalized recursive operators - by bo198214 - 03/07/2008, 06:58 PM
RE: Generalized recursive operators - by Ivars - 02/02/2008, 10:11 PM
RE: Generalized recursive operators - by Ivars - 02/03/2008, 10:41 AM
RE: Generalized recursive operators - by andydude - 02/11/2008, 09:47 PM
RE: Generalized recursive operators - by Ivars - 02/14/2008, 06:05 PM
RE: Generalized recursive operators - by GFR - 02/03/2008, 04:12 PM
RE: Generalized recursive operators - by Ivars - 02/03/2008, 08:48 PM
RE: Generalized recursive operators - by GFR - 02/06/2008, 02:44 PM
RE: Generalized recursive operators - by Ivars - 02/06/2008, 02:56 PM
RE: Generalized recursive operators - by Ivars - 02/06/2008, 03:43 PM
RE: Generalized recursive operators - by GFR - 03/10/2008, 09:53 PM
RE: Generalized recursive operators - by GFR - 03/11/2008, 10:24 AM
RE: Generalized recursive operators - by bo198214 - 03/11/2008, 10:53 AM
RE: Generalized recursive operators - by GFR - 03/12/2008, 12:13 AM
RE: Generalized recursive operators - by GFR - 03/13/2008, 06:41 PM
RE: Generalized recursive operators - by Stan - 04/04/2011, 11:52 PM

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