I was strugling to get in grips with infinite pentation of other base than e but failed.
So my question to experts:
Which y would satisfy the equation in the subject of the thread?
My guess is e^(-pi), so that:
e^(pi/2) [5] ( - infinity) = e^(-pi).
Ivars
So my question to experts:
Which y would satisfy the equation in the subject of the thread?
My guess is e^(-pi), so that:
e^(pi/2) [5] ( - infinity) = e^(-pi).
Ivars
