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Value of y slog(base (e^(pi/2))( y) = y

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Value of y slog(base (e^(pi/2))( y) = y
Ivars Offline
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02/03/2008, 04:40 PM (This post was last modified: 02/03/2008, 07:40 PM by Ivars.)
I was strugling to get in grips with infinite pentation of other base than e but failed.

So my question to experts:

Which y would satisfy the equation in the subject of the thread?

My guess is e^(-pi), so that:

e^(pi/2) [5] ( - infinity) = e^(-pi).

Ivars
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Value of y slog(base (e^(pi/2))( y) = y - by Ivars - 02/03/2008, 04:40 PM

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