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+--- Thread: Value of y slog(base (e^(pi/2))( y) = y (/showthread.php?tid=117)
Value of y slog(base (e^(pi/2))( y) = y - Ivars - 02/03/2008
I was strugling to get in grips with infinite pentation of other base than e but failed.
So my question to experts:
Which y would satisfy the equation in the subject of the thread?
My guess is e^(-pi), so that:
e^(pi/2) [5] ( - infinity) = e^(-pi).
Ivars
RE: Value of y slog(base (e^(pi/2))( y) = y - GFR - 02/03/2008
Thank you, Ivars. Let us see.
@ Andydude.
Could you please check the coordinates of the common intersection, for x < 0, and for b = e^(Pi/2), with your powerful slog and sexp machines, of:
- y = b # x = b-tetra-x;
- y = [base b]slog x, the inverse of the previous one;
- y = x, principal diagonal ?
The intersections of the three "tails" for x < 0 should correspond to b-penta(-oo).
But, I might be wrong.
GFR
RE: Value of y slog(base (e^(pi/2))( y) = y - Ivars - 02/22/2008
Is this very difficult or not interesting?
I still have not acquired software to be able to do it myself one day. I will proceed analytically, but that might take years
Ivars
RE: Value of y slog(base (e^(pi/2))( y) = y - bo198214 - 02/26/2008
Ivars Wrote:Is this very difficult or not interesting?
The value must be somewhere around -2 (far from your guess of \( e^{-\pi} \)) considering this picture showing the intersection of \( \text{slog}_{e^{\pi/2}} x \) with \( x \).
I guess it is not symboblically expressable with \( e \), \( i \) and \( \pi \).
But it is not exactly -2, because \( \text{slog}_b (x) > -2 \) for all real \( x \).
RE: Value of y slog(base (e^(pi/2))( y) = y - Ivars - 02/26/2008
Thanks!
Seems rather symmetrical, this value.
Ivars