Divergent Series and Analytical Continuation (LONG post)
#16
(02/26/2023, 11:52 AM)JmsNxn Wrote: Okay, so take this post with a Grain of salt. I wanted to look deeper into this question. Because my suspicion is that we can say that sometimes, these are natural analytic continuations. I apologize if this is dumb. I'm just spit balling Smile


I'd like to add my own two cents on:

\[
f(x) = \sum_{n=0}^\infty \frac{x^n}{1+x^n} \frac{1}{2^n}\\
\]

First of all, the word I used to use for these functions is a function that maps \(\mathbb{C} \to \mathbb{C}\) upto a measure zero set in \(\mathbb{C}\). In this case, the measure zero set is the unit circle \(U\). So that \(f : \mathbb{C}/U \to \mathbb{C}\). There is absolutely zero way to analytically continue these functions, or refer to them as analytic continuations of each other. By standard literature; they are two functions which are holomorphic on disjointed domains of \(\mathbb{C}\).

But yes, ONE is more natural; obviously the one which is just plugging in the number. This is a fallacy that Cauchy called the Generality of Algebra. And it was a stark criticism of Euler. Who upon which, Euler would use the Generality of Algebra to get correct results. But he also got incorrect results.

...

Lets define

\[
f(x) = \sum_{n=0}^\infty \frac{x^n}{1+x^n} \frac{1}{2^n}\\
\]

and
 g(x)

\[
g(x) = \sum_{n=0}^\infty \frac{x^n}{1+x^n} \frac{1}{3^n}\\
\]

Now there probably exist entire functions A(z),B(z) such that


A(f(z)) = B(g(z))

The idea was that taylor series of f or g would still have the same natural boundary because their powers do.
(although the multiplicity changes)


This leads to the idea that if we accept the continuation by plug-in for f and g then

Q(z) as a taylor expansion in two variables (a(z),b(z))
where a(z) = f(z) , b(z) = g(z)

starts to make sense.


Also

 \[
t(x) = \sum_{n=0}^\infty \frac{x^n}{1+x^n} 2^n\\
\]

by using 1 + 2 + 4 + 8 + ... = -1

might make sense.

t(1) = 

 \[
t(1) = \sum_{n=0}^\infty \frac{1}{1+1} 2^n\\
\]

so t(1) = - 1/2.


But we must be careful , we do not know if using such ideas is self-consistant with eachother.


I think this is somewhat in the spirit of what Caleb wanted to do.


regards

tommy1729
Reply


Messages In This Thread
RE: Divergent Series and Analytical Continuation (LONG post) - by tommy1729 - 02/26/2023, 09:33 PM

Possibly Related Threads…
Thread Author Replies Views Last Post
  Pictures of some generalized analytical continuations Caleb 18 19,357 03/17/2023, 12:56 AM
Last Post: tommy1729
  double functional equation , continuum sum and analytic continuation tommy1729 6 9,811 03/05/2023, 12:36 AM
Last Post: tommy1729
  Discussion on "tetra-eta-series" (2007) in MO Gottfried 40 42,239 02/22/2023, 08:58 PM
Last Post: tommy1729
  continuation of fix A to fix B ? tommy1729 22 23,643 02/06/2023, 11:59 PM
Last Post: tommy1729
Question Tetration Asymptotic Series Catullus 18 22,747 07/05/2022, 01:29 AM
Last Post: JmsNxn
Question Formula for the Taylor Series for Tetration Catullus 8 13,898 06/12/2022, 07:32 AM
Last Post: JmsNxn
  Calculating the residues of \(\beta\); Laurent series; and Mittag-Leffler JmsNxn 0 3,773 10/29/2021, 11:44 PM
Last Post: JmsNxn
  Trying to find a fast converging series of normalization constants; plus a recap JmsNxn 0 3,610 10/26/2021, 02:12 AM
Last Post: JmsNxn
  Reducing beta tetration to an asymptotic series, and a pull back JmsNxn 2 6,951 07/22/2021, 03:37 AM
Last Post: JmsNxn
  Hey, Everyone; been a long time... JmsNxn 17 28,187 01/28/2021, 09:53 AM
Last Post: MphLee



Users browsing this thread: 1 Guest(s)