01/20/2023, 12:45 AM
I want to point out some problems :
1) SUMMABILITY METHODS WORK GREAT TO GET A VALUE OF AN ANALYTIC CONTINUATION BUT OFTEN FAIL TO DETECT ( TRUE ) DIVERGEANCE !!
we still want to know about divergeance , also beyond the analytic continuation !
2) the entire function is an interpolation
so f(2^n) is defined as an f that grows like say f(x) = exp(x).
but almost any entire f that agrees with exp(x) at integer x can be used ... but might give different results !!
So a very disturbing thing.
3)
the sum 1 + 2 + 4 + ...
is associated to the equation 2 x = x - 1
or 4 x = x - 3
8 x = x - 7
etc
ALL of them give x = -1.
HOWEVER
the sum 1 + 3 + 9 + ...
has equations
3 x = x - 1
9 x = x - 1 - 3 = x - 4
etc
all with DIFFERENT solutions.
---
these " problems " are quite universal with summability methods.
Which is why " the master forbids it " ( being Weierstrass )
I do not forbid it , but be very careful.
regards
tommy1729
1) SUMMABILITY METHODS WORK GREAT TO GET A VALUE OF AN ANALYTIC CONTINUATION BUT OFTEN FAIL TO DETECT ( TRUE ) DIVERGEANCE !!
we still want to know about divergeance , also beyond the analytic continuation !
2) the entire function is an interpolation
so f(2^n) is defined as an f that grows like say f(x) = exp(x).
but almost any entire f that agrees with exp(x) at integer x can be used ... but might give different results !!
So a very disturbing thing.
3)
the sum 1 + 2 + 4 + ...
is associated to the equation 2 x = x - 1
or 4 x = x - 3
8 x = x - 7
etc
ALL of them give x = -1.
HOWEVER
the sum 1 + 3 + 9 + ...
has equations
3 x = x - 1
9 x = x - 1 - 3 = x - 4
etc
all with DIFFERENT solutions.
---
these " problems " are quite universal with summability methods.
Which is why " the master forbids it " ( being Weierstrass )
I do not forbid it , but be very careful.
regards
tommy1729

