Holomorphic semi operators, using the beta method
#55
(05/26/2022, 10:49 PM)JmsNxn Wrote: ...

This is because:

\[
\left(\alpha \uparrow^s z+1\right) - \left(\alpha \uparrow^{s-1} \left( \alpha \uparrow^s z\right)\right)\Big{|}_{s \in \mathbb{N}} = 0\\
\]
I snipped the part I completely understood.

This statement seems intuitively correct to me.
But Im still a bit troubled.
why positive integer s is sufficient and implies it for positive real s.

Maybe im tired.
I can see both are in the same vector space so that is good.

And we have countable parameters what seems good too ( implying countable s will be sufficient )

Maybe im lazy now.

But this matters alot

regards

tommy1729
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Messages In This Thread
RE: Holomorphic semi operators, using the beta method - by tommy1729 - 05/26/2022, 11:24 PM

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