07/06/2024, 02:59 AM

Hello. One day I was browsing Youtube, and I noticed a video that sprung me into thinking about tetration somehow. The Youtube video was a low effort math video and it said "Solve -a = 1/a", it will take anyone some basic algebra to figure out that a = i, thus, -i = 1/i. This was interesting to me, because I found it interesting the inverse orders of operations of different orders of magnitude have a result for a value which is the same and is a "unit" with magnitude 1 so to speak. This got me thinking about every "unit of dimensionality" for each operation in math. Let me know if you see a pattern:

0+1 = 1

1*-1 = -1

-1^(1/2) = i

So the next level in this step would be either the 1/2 tetration power of i or the 1/3 tetration power of i. This means that i = x^x or i = x^x^x.

The latter didn't net me any decent results, but I plugged i=x^x into Wolfram Alpha but I couldn't interpret it.

What I am adding to this tetration board is a postulate! I am postulating that there is an 'i' of tetration, where, like

1 = -(-1)

-i = 1/i,

there is a unit where

(1/x) = tetration(x,(1/2)),

This unit would follow the former pattern in the first list.

I got my undergrad in CS, so I may be a little out of my league, but let me know what you guys think.

-000_Era

0+1 = 1

1*-1 = -1

-1^(1/2) = i

So the next level in this step would be either the 1/2 tetration power of i or the 1/3 tetration power of i. This means that i = x^x or i = x^x^x.

The latter didn't net me any decent results, but I plugged i=x^x into Wolfram Alpha but I couldn't interpret it.

What I am adding to this tetration board is a postulate! I am postulating that there is an 'i' of tetration, where, like

1 = -(-1)

-i = 1/i,

there is a unit where

(1/x) = tetration(x,(1/2)),

This unit would follow the former pattern in the first list.

I got my undergrad in CS, so I may be a little out of my league, but let me know what you guys think.

-000_Era