05/07/2016, 12:28 PM
Essentially my matrix method is based on solving
F(x) = F(exp(x)) - 1
In terms of Taylor series.
We pick the expansion point x = 0 because the distance
Between the curve exp and id is minimum at x=0.
This is mentioned before here
http://math.eretrandre.org/tetrationforu....php?tid=3
The way I solve the infinite matrix is different.
First i solve the truncated linear with 7 variables and 6 equations.
And then minimize the Sum of squares for them.
Now i plug in the value of these 7 variables into the truncation 16 variables and 8 equations and again minimize the Sum of squares.
Then continue 34 equations and 17 variables etc etc.
By minimizing the Sum of squares we get the highest possible radius ( Up to the fixpoint ).
Since that radius extends to 1 we are Done.
Regards
Tommy1729
F(x) = F(exp(x)) - 1
In terms of Taylor series.
We pick the expansion point x = 0 because the distance
Between the curve exp and id is minimum at x=0.
This is mentioned before here
http://math.eretrandre.org/tetrationforu....php?tid=3
The way I solve the infinite matrix is different.
First i solve the truncated linear with 7 variables and 6 equations.
And then minimize the Sum of squares for them.
Now i plug in the value of these 7 variables into the truncation 16 variables and 8 equations and again minimize the Sum of squares.
Then continue 34 equations and 17 variables etc etc.
By minimizing the Sum of squares we get the highest possible radius ( Up to the fixpoint ).
Since that radius extends to 1 we are Done.
Regards
Tommy1729