I thought I'd take a crack at base = 1/2
#2
Here's the code I've used for these functions. I've made it to about 10 digit precision. I've set the iterations to 100 by default. So we're looking for \( \mu_\lambda^{100} \). It works nearly flawlessly, still a little sketchy though.


.zip   Abel_half_T.zip (Size: 979 KB / Downloads: 617)
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RE: I thought I'd take a crack at base = 1/2 - by JmsNxn - 09/25/2021, 07:11 AM

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