Exploring Pentation - Base e
#2
I came to a similar conclusion in this thread, only using a linear approximation, and our results seem to agree, especially on the specific value: \( x{\uparrow}{\uparrow}{\uparrow}-2 = -1 \).

Andrew Robbins
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Messages In This Thread
Exploring Pentation - Base e - by jaydfox - 12/18/2007, 02:57 PM
RE: Exploring Pentation - Base e - by andydude - 12/18/2007, 04:45 PM
RE: Exploring Pentation - Base e - by jaydfox - 12/19/2007, 06:01 AM
RE: Exploring Pentation - Base e - by Ivars - 01/28/2008, 11:01 AM
RE: Exploring Pentation - Base e - by Ivars - 02/02/2008, 05:05 PM
RE: Exploring Pentation - Base e - by Ivars - 02/02/2008, 10:50 PM
RE: Exploring Pentation - Base e - by GFR - 02/02/2008, 11:01 PM
RE: Exploring Pentation - Base e - by Ivars - 02/04/2008, 08:07 PM
RE: Exploring Pentation - Base e - by quickfur - 02/22/2008, 12:21 AM
RE: Exploring Pentation - Base e - by GFR - 02/04/2008, 09:19 PM
RE: Exploring Pentation - Base e - by Ivars - 02/05/2008, 11:25 PM
RE: Exploring Pentation - Base e - by GFR - 02/06/2008, 03:01 PM
RE: Exploring Pentation - Base e - by Ivars - 02/06/2008, 06:23 PM
RE: Exploring Pentation - Base e - by Ivars - 02/07/2008, 09:00 PM
RE: Exploring Pentation - Base e - by Ivars - 02/07/2008, 09:30 PM
RE: Exploring Pentation - Base e - by Ivars - 02/07/2008, 11:20 PM
RE: Exploring Pentation - Base e - by Ivars - 02/08/2008, 10:32 AM
RE: Exploring Pentation - Base e - by Ivars - 02/08/2008, 10:51 AM
RE: Exploring Pentation - Base e - by Ivars - 02/08/2008, 10:56 AM
RE: Exploring Pentation - Base e - by Ivars - 02/09/2008, 11:12 PM
RE: Exploring Pentation - Base e - by Ivars - 02/15/2008, 08:24 PM
RE: Exploring Pentation - Base e - by Ivars - 03/03/2008, 08:04 PM

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