f(s),h(s) and "hairs".
#3
What do you mean with f? Your f in the definition satisfies f(s+1)=exp(f(s))? Or is f(s+1)=exp(f(s))+something(s)

Quote:If f(s) was exactly tetration those paths would be flat and parallel to eachother
I don't see how this can be true. If wee see hair(a) as a path (curve) I don't see it being "flat", aka a line. They are the images of rays in the complex planes (parallel to the x axis) under the function f but when f maps them I expect them to curve even in the case of tetration. Or do you mean "flat" in another way?

Mother Law \(\sigma^+\circ 0=\sigma \circ \sigma^+ \)

\({\rm Grp}_{\rm pt} ({\rm RK}J,G)\cong \mathbb N{\rm Set}_{\rm pt} (J, \Sigma^G)\)
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Messages In This Thread
f(s),h(s) and "hairs". - by tommy1729 - 05/20/2021, 11:54 PM
RE: f(s),h(s) and "hairs". - by tommy1729 - 05/21/2021, 12:01 AM
RE: f(s),h(s) and "hairs". - by MphLee - 05/21/2021, 05:32 PM
RE: f(s),h(s) and "hairs". - by Gottfried - 05/21/2021, 07:23 PM
RE: f(s),h(s) and "hairs". - by tommy1729 - 05/22/2021, 12:24 PM
RE: f(s),h(s) and "hairs". - by JmsNxn - 05/23/2021, 12:42 AM



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