Convergence of matrix solution for base e
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Convergence of matrix solution for base e
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12/14/2007, 07:20 AM
So let me get this straight. On the first graph you are plotting arg-vs-log(err) and on the second graph you are plotting log(size)-vs-log(err), is that right? I think that would mean the direct quantities would have a power relationship, if \( \log(E) = -6.8\log(n) \) then \( E = n^{-6.8} < n^{-6} \) which means you may have found an upper bound for the error.
Wow! Andrew Robbins |
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Convergence of matrix solution for base e - by jaydfox - 12/13/2007, 02:05 AM
RE: Convergence of matrix solution for base e - by jaydfox - 12/13/2007, 02:13 AM
RE: Convergence of matrix solution for base e - by andydude - 12/14/2007, 07:20 AM
RE: Convergence of matrix solution for base e - by jaydfox - 12/14/2007, 05:55 PM
RE: Convergence of matrix solution for base e - by jaydfox - 12/15/2007, 04:43 AM
RE: Convergence of matrix solution for base e - by jaydfox - 12/17/2007, 01:58 PM
RE: Convergence of matrix solution for base e - by jaydfox - 12/18/2007, 12:14 AM
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