Roots of z^z^z+1 (pictures in MSE) [update 8'2022]
#2
Note since \( ^3 z+1=0 \), that 
\( ^3 z=-1 \) 
\( ^4 z=1/z \)
\( ^5z=z^{1/z} \) 
where \( z^{1/z} \) is related to the Shell Thron boundary. So 
\( ^nz \) 
would be related to an iterated Shell Thron boundary.
Daniel
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RE: Roots of z^z^z+1 (pictures in MSE) - by Daniel - 02/08/2020, 01:45 AM

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