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UnAbel to do that

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UnAbel to do that
bo198214 Offline
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#2
07/20/2019, 10:16 PM
If you have a Schröder solution \( s(f(x))=cs(x) \) then you also have an Abel solution \( a(f(x))=1+a(x) \), by \( a(x)=\log_c(s(x)) \). Can't remember where the Schröder solution was introduced (am on travel - limited resources).
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Messages In This Thread
UnAbel to do that - by Daniel - 07/20/2019, 03:39 PM
RE: UnAbel to do that - by bo198214 - 07/20/2019, 10:16 PM
RE: UnAbel to do that - by Daniel - 07/21/2019, 01:29 AM
RE: UnAbel to do that - by sheldonison - 07/21/2019, 08:54 PM
RE: UnAbel to do that - by Daniel - 07/22/2019, 12:24 AM
RE: UnAbel to do that - by sheldonison - 07/23/2019, 03:13 AM



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