01/18/2019, 06:42 AM
(01/18/2019, 06:35 AM)jaydfox Wrote: The good news is, the acceleration can be taken a step further, by removing the algebraic singularity that remains after removing the logarithmic singularity. A few years ago, I determined that my accelerated solution appears to be converging on an algebraic singularity in terms of \( (z-L)^{2\pi i / L} \), or rather a power series in such. (I typically call the fixed point a in my code, but I'm using L here, since that's what you mentioned in your post.)
I can't remember now if the exponent for the algebraic term is 2*pi*i/L, or if it's the reciprocal, L/(2*pi*i). I apologize if I had the fraction upside down. I don't have my notes in front of me, so I'm doing this from memory. When I get around to posting more details on the algebraic singularity, I'll be sure to clarify the exponent and provide a proof.
~ Jay Daniel Fox

