So we need to show f = exp(z) (1+x^2) + z is surjective to the complex plane.
F maps [- oo , oo ] to [- oo , oo ].
Also conj(f(z)) = f(conj(z)).
Hence f is surjective on the reals.
By picard if f(z) =\= L then this L is unique.
But by the above f(conj(z)) =\= conj L.
Hence contradicting picard.
Therefore f is surjective to the complex plane.
So the singularities of its super are bounded.
Q.E.D.
Regards
Tommy1729
F maps [- oo , oo ] to [- oo , oo ].
Also conj(f(z)) = f(conj(z)).
Hence f is surjective on the reals.
By picard if f(z) =\= L then this L is unique.
But by the above f(conj(z)) =\= conj L.
Hence contradicting picard.
Therefore f is surjective to the complex plane.
So the singularities of its super are bounded.
Q.E.D.
Regards
Tommy1729

