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Should tetration be a multivalued function?

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Should tetration be a multivalued function?
marraco Offline
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#18
01/14/2016, 04:24 AM
(01/09/2016, 05:56 PM)marraco Wrote: The general equation is \( \\[15pt]

{(^xa)^{^{y}a}=(^{y+1}a)^{^{x-1}a}} \)

Because \( \\[20pt]

{(^xa)^{^{y}a}\,=\,(a^{^{x-1}a})^{^{y}a}}\,=\,a^{^{x-1}a.\,^{y}a}\,=\,(a^{^{y}a})^{^{x-1}a}\,=\,(^{y+1}a)^{^{x-1}a } \)

It is somewhat trivial.

I just noticed that the equation remains valid between branches, and "branches" include the asymptotes.

[Image: BGuN4lj.jpg?1]
I have the result, but I do not yet know how to get it.
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Messages In This Thread
RE: Should tetration be a multivalued function? - by marraco - 01/14/2016, 04:24 AM

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