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Should tetration be a multivalued function?

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Should tetration be a multivalued function?
marraco Offline
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#13
01/09/2016, 05:56 PM (This post was last modified: 01/09/2016, 06:17 PM by marraco.)
The general equation is \( \\[15pt]

{(^xa)^{^{y}a}=(^{y+1}a)^{^{x-1}a}} \)

Because \( \\[20pt]

{(^xa)^{^{y}a}\,=\,(a^{^{x-1}a})^{^{y}a}}\,=\,a^{^{x-1}a.\,^{y}a}\,=\,(a^{^{y}a})^{^{x-1}a}\,=\,(^{y+1}a)^{^{x-1}a } \)

It is somewhat trivial.
I have the result, but I do not yet know how to get it.
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Messages In This Thread
RE: Should tetration be a multivalued function? - by marraco - 01/09/2016, 05:56 PM

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