Superroots and a generalization for the Lambert-W
#22
I think super-roots are important.

Iterated exponentials (\( w = \exp_x^{y}(z) \)) are a function of three variables (trivariate? function), and so they have 3 inverse functions: negatively iterated exponentials (solving for z), trivariate super-logarithms (solving for y), and trivariate super-roots (solving for x). Trivariate super-logarithms can be expressed with bivariate super-logarithms, and so are not fundamental operations, but trivariate super-roots have no known expression in terms of bivariate super-roots, and so are, so far, a fundamental operation so far as I know.

My recent research into super-roots have convinced me that we know more about them than we think we know. We can calculate the derivatives of them to a rational number in some cases, and to any precision in other cases. Using a combination of power series and Lagrange inverse series, we can calculate many many things about them, but we still don't have a closed form for these apparently useful functions. I think that given enough time, effort, and insight, we can find at least a recurrence equation that expresses how to find super-root (n + 1) given complete knowledge of super-root (n).

I'm going to go out on a limb and make a notation for these trivariate super-roots:
  • \( \sqrt[y]{w}^{(z)}_{\mathrm{s}} = x \) iff. \( w = \exp_x^y(z) \)
One of the advantages of trivariate super-roots is that they have more algebraic identities regarding them:
  • \( \sqrt[y]{w}^{(z)}_{\mathrm{s}}
    = \sqrt[y]{x^w}^{(x^z)}_{\mathrm{s}}
    = \sqrt[(y-1)]{w}^{(x^z)}_{\mathrm{s}}
    = x \)
and there is one about the third super-root:
  • \( \sqrt[3]{w}^{(z)}_{\mathrm{s}}
    = \left(\sqrt[2]{w^z}^{\left(\frac{x^z}{z}\right)}_{\mathrm{s}}\right)^{1/z}
    = x \)
and there is one about the second super-root:
  • \( \sqrt[2]{w}^{(z)}_{\mathrm{s}}
    = \left(\sqrt[2]{w^z}^{(1)}_{\mathrm{s}}\right)^{1/z}
    = x \)
where \( \sqrt[2]{w}^{(1)}_{\mathrm{s}} \) just means the bivariate super-root \( \sqrt[2]{w}_{\mathrm{s}} \).

If we could find a general way of expressing trivariate super-roots in terms of bivariate super-roots, then I think we would know much more about tetration than we do today. Perhaps along the way we will discover something new that will shed some light on super-logarithms, too, perhaps.

Regards,
Andrew Robbins
Reply


Messages In This Thread
RE: Superroots and a generalization for the Lambert-W - by andydude - 12/09/2015, 06:34 AM

Possibly Related Threads…
Thread Author Replies Views Last Post
  Nixon-Banach-Lambert-Raes tetration is analytic , simple and “ closed form “ !! tommy1729 11 19,426 02/04/2021, 03:47 AM
Last Post: JmsNxn
  Superroots (formal powerseries) Gottfried 10 37,372 04/05/2011, 03:22 AM
Last Post: Stan
  Infinite towers & solutions to Lambert W-function brangelito 1 10,055 06/16/2010, 02:50 PM
Last Post: bo198214
  Lambert W function and the Super Square Root James Knight 3 19,380 10/29/2009, 06:30 AM
Last Post: andydude
  the extent of generalization Matt D 11 35,538 10/15/2007, 04:52 PM
Last Post: Matt D



Users browsing this thread: 1 Guest(s)