Bicomplex helpers
#1
I started using bicomplex numbers instead of complex Numbers.

The reason is that for most complex Numbers , continue iterations result in loops.

We use as norm for the bicomplex numbers the complex Numbers.

For instance :

Avoid a fixpoint for x^2 , start with complex norm 1.

J^2 = 1.
We use (1/3 + 2/3 j)^2 = 5/9 + 4/9 j.
Thus not a fixpoint !
But both lhs and rhs has norm 1.

This is powerful.

Regards

Tommy1729
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Messages In This Thread
Bicomplex helpers - by tommy1729 - 11/25/2015, 01:24 PM
RE: Bicomplex helpers - by tommy1729 - 11/25/2015, 01:27 PM



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